f(x) = (1 + x)(2 + x2)1/2(3 + x3)1/3. Find f '(-1).
Solution
Differentiating gives f '(x) = (2 + x2)1/2(3 + x3)1/3 + terms with factor (1 + x). Hence f '(-1) =31/221/3.
1st VMO 1962
© John Scholes jscholes@kalva.demon.co.uk 8 July 2002
