45th Putnam 1984

------
 
 
Problem A5

V is the pyramidal region x, y, z >= 0, x + y + z <= 1. Evaluate ∫V x y9 z8 (1 - x - y - z)4 dx dy dz.

 

Solution

Answer: 9! 8! 4! / 25! .

The most straightforward approach is simply to carry out the integrations. This gets slightly messy, gives no insight into what is going on, and carries the risk of error. On the other hand, it is not that bad and it gets the answer reliably and quickly.

Integrate first over x, from 0 to 1 - y - z. The indefinite integral has two terms - x(1 - x - y - z)5y9z8/5 - (1 - x - y - z)6y9z8/30. The first gives zero and the second gives y9z8(1 - y - z)6/30.

Now integrate over z, from 0 to 1 - y. Ignoring the constant factor y9/30, we get 7 terms z9(1 - y - z)6/9 + ... + z15 (6! 8!)/15! . The first 6 integrate to zero. The last gives that the required integral I = 6! 8! /(15! 30) ∫01 y9(1 - y)15 dy. The integral from 0 to 1 is 9! 15! / 25! Hence the result.

 


 

45th Putnam 1984

© John Scholes
jscholes@kalva.demon.co.uk
7 Jan 2001