IMO 1973

------
 
 
Problem B3

a1, a2, ... , an are positive reals, and q satisfies 0 < q < 1. Find b1, b2, ... , bn such that:

(a)  ai < bi for i = 1, 2, ... , n,

(b)  q < bi+1/bi < 1/q for i = 1, 2, ... , n-1,

(c)  b1 + b2 + ... + bn < (a1 + a2 + ... + an)(1 + q)/(1 - q).

 

Solution

We notice that the constraints are linear, in the sense that if bi is a solution for ai, q, and bi' is a solution for ai', q, then for any k, k' > 0 a solution for kai + k'ai', q is kbi + k'bi'. Also a "near" solution for ah = 1, other ai = 0 is b1 = qh-1, b2 = qh-2, ... , bh-1 = q, bh = 1, bh+1 = q, ... , bn = qn-h. "Near" because the inequalities in (a) and (b) are not strict.

However, we might reasonably hope that the inequalities would become strict in the linear combination, and indeed that is true. Define br = qr-1a1 + qr-2a2 + ... + qar-1 + ar + qar+1 + ... + qn-ran. Then we may easily verify that (a) - (c) hold.

 


Solutions are also available in:   Samuel L Greitzer, International Mathematical Olympiads 1959-1977, MAA 1978, and in   István Reiman, International Mathematical Olympiad 1959-1999, ISBN 189-8855-48-X.

 

15th IMO 1973

© John Scholes
jscholes@kalva.demon.co.uk
10 Oct 1998